10 questions · Form 4 Additional Mathematics Bab 5: Progressions
10 questions · plays in fullscreen
Prefer reading to quizzing? All 10 questions are listed below with the answer and explanation under each one.
1. The sum to infinity of a GP is 27 and its common ratio is 13. Find the first term a.
Answer: A
S_∞ = a1 - r => 27 = a / (1 - 13) => 27 = a / (23) => a = 27 × (23) = 18.
2. Find the common difference of the AP whose n-th term is T_n = 5 - 3n.
Answer: A
T₁ = 5 - 3(1) = 2. T₂ = 5 - 3(2) = -1. d = T₂ - T₁ = -1 - 2 = -3.
3. Under what condition does a geometric progression have a sum to infinity (S_∞)?
Answer: A
A infinite geometric progression converges to a finite sum if and only if |r| < 1, which means -1 < r < 1.
4. Find the sum to infinity of the geometric progression: 12, 4, 43, 49, ...
Answer: A
a = 12, r = 412 = 13. S_∞ = a1 - r = 12 / (1 - 13) = 12 / (23) = 18.
5. The 3rd term of an AP is 10 and the 8th term is 25. Find the common difference d.
Answer: A
T₃ = a + 2d = 10, T₈ = a + 7d = 25. Subtracting equations: 5d = 15 => d = 3.
6. Find the common ratio r of the geometric progression: 162, -54, 18, -6, ...
Answer: A
r = T₂ / T₁ = -54162 = -13.
7. Express the recurring decimal 0.4444... as a fraction in its simplest form using sum to infinity.
Answer: A
0.4444... = 0.4 + 0.04 + 0.004 + ... which is a GP with a = 0.4, r = 0.1. S_∞ = 0.41 - 0.1 = 0.40.9 = 49.
8. An employee's starting annual salary is RM 36 000 with an annual increment of RM 2 400. Calculate total salary earned after 10 years.
Answer: A
AP with a = 36000, d = 2400, n = 10. S₁₀ = (102)[2(36000) + 9(2400)] = 5[72000 + 21600] = 5[93600] = RM 468 000.
9. Three consecutive terms of an arithmetic progression are x - 1, x + 3, and 3x + 1. Find the value of x.
Answer: A
In an AP, (T₂ - T₁) = (T₃ - T₂) => (x + 3) - (x - 1) = (3x + 1) - (x + 3) => 4 = 2x - 2 => 2x = 6 => x = 3.
10. Calculate the sum of the first 20 terms of the arithmetic progression: 2, 5, 8, 11, ...
Answer: A
a = 2, d = 3, n = 20. S₂₀ = (202)[2(2) + (20 - 1)(3)] = 10[4 + 57] = 10[61] = 610.